40x=-4x^2-100

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Solution for 40x=-4x^2-100 equation: 



40x=-4x^2-100

We move all terms to the left:

40x-(-4x^2-100)=0

We get rid of parentheses

4x^2+40x+100=0

a = 4; b = 40; c = +100;
Δ = b2-4ac
Δ = 402-4·4·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{8}=-5$

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